MySQL按小时查询数据,没有的补0

需求背景

最近的需求,记录一下。一个统计表数据的接口,前端需要返回两个数组,一个是0-23的小时计数,一个是各小时对应的统计数。

思路

  1. 直接使用group by查询要统计的表,当某个小时统计数为0时,会没有该小时分组。思考了一下,需要建立辅助表,只有一列小时,再插入0-23共24个小时
1
2
3
CREATE TABLE hours_list (
hour int NOT NULL PRIMARY KEY
)
  1. 先查小时表,再做连接需要查的表,即可将没有统计数的小时填充上0。这里由于需要查多个表中,create_time在每个小时区间内、且SOURCE_ID等于查询条件的统计之和,所以UNION ALL了多张表
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
SELECT
t.HOUR,
sum(t.HOUR_COUNT) hourCount
FROM
(SELECT
hs. HOUR AS HOUR,
COUNT(cs.RECORD_ID) AS HOUR_COUNT
FROM
cbc_hours_list hs
LEFT JOIN cbc_source_0002 cs ON HOUR (cs.create_time) = hs. HOUR
AND cs.create_time > #{startTime}
AND cs.create_time <= #{endTime}
<#if sourceId?exists && sourceId !=''>
AND SOURCE_ID = #{sourceId}
</#if>
GROUP BY
hs. HOUR
UNION ALL
SELECT
hs.HOUR AS HOUR,
COUNT(cs.RECORD_ID) AS HOUR_COUNT
FROM
cbc_hours_list hs
LEFT JOIN cbc_source_hs cs ON HOUR (cs.create_time) = hs. HOUR
AND cs.create_time > #{startTime}
AND cs.create_time <= #{endTime}
<#if sourceId?exists && sourceId !=''>
AND SOURCE_ID = #{sourceId}
</#if>
GROUP BY
hs. HOUR
UNION ALL
SELECT
hs.HOUR AS HOUR,
COUNT(cs.RECORD_ID) AS HOUR_COUNT
FROM
cbc_hours_list hs
LEFT JOIN cbc_source_kfyj cs ON HOUR (cs.create_time) = hs. HOUR
AND cs.create_time > #{startTime}
AND cs.create_time <= #{endTime}
<#if sourceId?exists && sourceId !=''>
AND SOURCE_ID = #{sourceId}
</#if>
GROUP BY
hs. HOUR
UNION ALL
SELECT
hs.HOUR AS HOUR,
COUNT(cs.RECORD_ID) AS HOUR_COUNT
FROM
cbc_hours_list hs
LEFT JOIN cbc_source_his_0002 cs ON HOUR (cs.create_time) = hs. HOUR
AND cs.create_time > #{startTime}
AND cs.create_time <= #{endTime}
<#if sourceId?exists && sourceId !=''>
AND SOURCE_ID = #{sourceId}
</#if>
GROUP BY
hs. HOUR
UNION ALL
SELECT
hs.HOUR AS HOUR,
COUNT(cs.RECORD_ID) AS HOUR_COUNT
FROM
cbc_hours_list hs
LEFT JOIN cbc_source_his_hs cs ON HOUR (cs.create_time) = hs. HOUR
AND cs.create_time > #{startTime}
AND cs.create_time <= #{endTime}
<#if sourceId?exists && sourceId !=''>
AND SOURCE_ID = #{sourceId}
</#if>
GROUP BY
hs. HOUR
UNION ALL
SELECT
hs.HOUR AS HOUR,
COUNT(cs.RECORD_ID) AS HOUR_COUNT
FROM
cbc_hours_list hs
LEFT JOIN cbc_source_his_kfyj cs ON HOUR (cs.create_time) = hs. HOUR
AND cs.create_time > #{startTime}
AND cs.create_time <= #{endTime}
<#if sourceId?exists && sourceId !=''>
AND SOURCE_ID = #{sourceId}
</#if>
GROUP BY
hs. HOUR) t
GROUP BY
t.hour

效果

统计数为0的小时也可以查出来了。

0%